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JEE Main202126 Feb 2021Morning ShiftMathematicsSets and RelationsActual

Let R = P , Q | P and Q are at the same distance from the origin be a relation, then the equivalence class of 1 , - 1 is the set

Options

  1. AS = x , y | x 2 + y 2 = 1
  2. BS = x , y | x 2 + y 2 = 2
  3. CS = x , y | x 2 + y 2 = 2
  4. DS = x , y | x 2 + y 2 = 4

Correct answer

B. S = x , y | x 2 + y 2 = 2

Step-by-step solution

Equivalence class of 1 , - 1 is a circle with centre at 0 , 0 and radius = 2 ⇒ x 2 + y 2 = 2 S = x , y | x 2 + y 2 = 2

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