JEE Main20198 Apr 2019Morning ShiftMathematicsStraight LinesActual

A point on the straight line, 3 x + 5 y = 15 which is equidistant from the coordinate axes will lie only in:

Options

A1 s t and 2 n d quadrants
B1 s t , 2 n d and 4 th quadrants
C1 s t quadrant
D4 t h quadrant

Correct answer

A. 1 s t and 2 n d quadrants

Step-by-step solution

Let a , a be a point on the line 3 x + 5 y = 15 ⇒ 3 a + 5 a = 15 ⇒ a = 15 8 ∴   Point is 15 8   , 15 8 which lies in 1 s t   quadrant Again, Let - a , a be a point on the line 3 x + 5 y = 15 ⇒ - 3 a + 5 a = 15 ⇒ a = 15 2 ∴   Point is - 15 2   , 15 2 which lies in 2 n d   quadrant Hence, required point lies in 1 s t and 2 n d quadrants.

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