If a straight line passing through the point P(- 3, 4) is such that...

Let the line passing through $\left(- 3, 4\right)$ intersect the coordinate axes at A&B$.</p><p>By mid-point formula, co-ordinates of$P\left(\dfrac{\alpha + 0}{2}, \dfrac{0 + \beta}{2}\right)$.</p><p>Comparing with given co-ordinate values, we get</p><p>$\dfrac{\alpha + 0}{2} = - 3 ⇒ \alpha = - 6$</p><p>and$\dfrac{\beta + 0}{2} = 4 ⇒ \beta = 8$</p><p>Hence, equation of line is$\dfrac{x}{- 6} + \dfrac{y}{8} = 1$</p><p>$⇒ 4x - 3y + 24 = 0