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JEE Main201912 Jan 2019Evening ShiftMathematicsStraight LinesActual

If a straight line passing through the point P - 3 , 4 is such that its intercepted portion between the coordinate axes is bisected at P , then its equation is :

Options

  1. A4 x + 3 y = 0
  2. B4 x - 3 y + 24 = 0
  3. C3 x - 4 y + 25 = 0
  4. Dx - y + 7 = 0

Correct answer

B. 4 x - 3 y + 24 = 0

Step-by-step solution

Let the line passing through - 3 ,   4 intersect the coordinate axes at A & B . By mid-point formula, co-ordinates of P α + 0 2 ,   0 + β 2 . Comparing with given co-ordinate values, we get α + 0 2 = - 3 ⇒ α = - 6 and β +   0 2 = 4 ⇒ β = 8 Hence, equation of line is x - 6 + y 8 = 1 ⇒ 4 x - 3 y + 24 = 0

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