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If the point (1, a) lies between the straight lines x+y=1 and 2(x+y)=3 then a lies in interval

Options

  1. A( 3 2 , )
  2. B(1, 3 2 )
  3. C(- , 0)
  4. D(0, 1 2 )

Correct answer

D. (0, 1 2 )

Step-by-step solution

Since, (1, a) lies between x+y=1 and 2(x+y)=3 Put x=1 in 2(x+y)=3 . We get the range of y . Thus, 2(1+y)=3 y= 3 2 -1= 1 2 Thus ' a 'lies in (0, 1 2 )

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