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JEE Main 201212 MayOnline
Exam
JEE Main
Year
2012
Date
12 May
Mode
Online
Subject
Mathematics
Chapter
Straight Lines

JEE Main 2012 · 12 May · Online · Mathematics · Straight Lines

If two vertices of a triangle are (5,-1) and (-2,3) and its...

If two vertices of a triangle are (5,−1)(5,-1) and (−2,3)(-2,3) and its orthocentre is at (0,0)(0,0), then the third vertex isIf two vertices of a triangle are (5,-1) and (-2,3) and its orthocentre is at (0,0) , then the third vertex isIf two vertices of a triangle are (5,-1) and (-2,3) and its orthocentre is at (0,0) , then the third vertex is

Options

  1. A(4,−7)(4,-7)
  2. B(−4,−7)(-4,-7)
  3. C(−4,7)(-4,7)
  4. D(4,7)(4,7)

Correct answer

B. (−4,−7)(-4,-7)

Step-by-step solution

If two vertices of a triangle are (5,-1) and (-2,3) and its orthocentre is at (0,0) , then the third vertex is
Let the third vertex of △ABC\triangle A B C be (a,b)(a, b). Orthocentre =H(0,0)=H(0,0) Let A(5,−1)andB(−2,3)A(5,-1) and B(-2,3) be other two vertices of △ABC\triangle A B C. Now, (Slope of AH)×(A H) \times( Slope of BC)=−1B C)=-1⇒(−1−05−0)(b−3a+2)=−1⇒b−3=5(a+2)\begin{aligned}& \Rightarrow\left(\frac{-1-0}{5-0}\right)\left(\frac{b-3}{a+2}\right)=-1 \\ & \Rightarrow b-3=5(a+2) \end{aligned}Similarly,Similarly,(SlopeofSlope ofB H) \times(SlopeofSlope ofA C)=-1 ⇒−(32)×(b+1a−5)=−1⇒3b+3=2a−10⇒3b−2a+13=0\begin{aligned}& \Rightarrow \quad-\left(\frac{3}{2}\right) \times\left(\frac{b+1}{a-5}\right)=-1 \\ & \Rightarrow \quad 3 b+3=2 a-10 \\ & \Rightarrow 3 b-2 a+13=0 \end{aligned} On solving equation (1)and(2)wegeta=−4,b=−7and (2) we geta=-4, b=-7 Hence, third vertex is (−4,−7)(-4,-7).
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