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JEE Main 20127 MayOnline
Exam
JEE Main
Year
2012
Date
7 May
Mode
Online
Subject
Mathematics
Chapter
Straight Lines

JEE Main 2012 · 7 May · Online · Mathematics · Straight Lines

If the straight lines x+3 y=4,3 x+y=4 and x+y =0 form a triangle,...

If the straight lines x+3y=4,3x+y=4x+3 y=4,3 x+y=4 and x+yx+y =0=0 form a triangle, then the triangle is

Options

  1. Ascalene
  2. Bequilateral triangle
  3. Cisosceles
  4. Dright angled isosceles

Correct answer

C. isosceles

Step-by-step solution

Let equation of AB:x+3y=4A B: x+3 y=4 Let equation of BC:3x+y=4B C: 3 x+y=4 Let equation of CA:x+y=0C A: x+y=0 Now, By solving these equations we get A=(−2,2),B=(1,1)A=(-2,2), B=(1,1) and C=(2,−2)C=(2,-2) Now, AB=9+1=10A B=\sqrt{9+1}=\sqrt{10}, B C=1+9=10\sqrt{1+9}=\sqrt{10}and CA=16+16=32C A=\sqrt{16+16}=\sqrt{32} Since, length of ABA B and BCB C are same therefore triangle is isosceles.
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