Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main20262 April 2026Evening ShiftMathematicsThree Dimensional GeometryActual

Let the point A be the foot of perpendicular drawn from the point P(a, b, 0) on the line x-1 2 = y-2 1 = z- 3 . If the midpoint of the line segment PA is (0, 3 4 , -1 4 ) , then the value of a^2 + b^2 + ^2 is equal to:

Options

  1. A1
  2. B2
  3. C6
  4. D9

Correct answer

A. 1

Step-by-step solution

Let P = (a, b, 0) and the midpoint of PA be M = (0, 3 4 , - 1 4 ) . Using the midpoint formula, the coordinates of A are given by 2M - P : A = (-a, 3 2 - b, - 1 2 ) Since A lies on the given line x-1 2 = y-2 1 = z- 3 = , we can write: -a-1 2 = a = -2 - 1 3 2 -b-2 1 = b = - - 1 2 - 1 2 - 3 = = -3 - 1 2 The direction ratios of the line segment PA are the differences in coordinates of A and P : PA = (-2a, 3 2 - 2b, - 1 2 ) Since PA is perpendicular to the given line, the dot product of their direction ratios must be z

Practice Three Dimensional Geometry on Quantrex Academy →

More from Three Dimensional Geometry

Let P be the plane such that it contains the straight line x-1 2 = y-3 3 = z+2 1 and is perpendicular to the plane x + 2y + 3z = 4 . Let P₁ be the plane which passes through the po 2026Let L be the straight line joining the points P(1, 2, -1) and Q(2, 3, 1) . Let S be the foot of the perpendicular drawn from the point R(4, -1, 5) to the line L . Another line pass 2026Let the foot of perpendicular from the point ( , 2, 3) on the line x-4 1 = y-9 2 = z-5 1 be the point (1, , 2) . Then the distance between the lines x-1 2 = y-2 3 = z+4 6 and x- 2 2026Let a line L₁ pass through the origin and be perpendicular to the lines L₂: r = (3+t) i + (2t-1) j + (2t+4) k and L₃: r = (3+2s) i + (3+2s) j + (2+s) k , t, s R . If (a, b, c) , a 2026The shortest distance between the lines x-4 1 = y-3 2 = z-2 -3 and x+2 2 = y-6 4 = z-5 -5 is : 2026Let the image of the point P(0, -5, 0) in the line x-1 2 = y 1 = z+1 -2 be the point R and the image of the point Q (0, -1 2 , 0 ) in the line x-1 -1 = y+9 4 = z+1 1 be the point S 2026Let the image of the point P(1, 6, a) in the line L: x 1 = y-1 2 = z-a+1 b , b > 0 , be ( a 3 , 0, a+c ) . If S( , , ) , > 0 , is the point on L such that the distance of S from th 2026Let a line L be perpendicular to both the lines L₁: x+1 3 = y+3 5 = z+5 7 and L₂: x-2 1 = y-4 4 = z-6 7 . If is the acute angle between the lines L and L₃: x - 8 7 2 = y - 4 7 1 = 2026 Full Three Dimensional Geometry list All JEE Main PYQs