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JEE Main20254 Apr 2025Morning ShiftMathematicsThree Dimensional GeometryActual

Let the shortest distance between the lines x-3 3 = y- -1 = z-3 1 and x+3 -3 = y+7 2 = z- 4 be 3 30 . Then the positive value of 5 + is

Options

  1. A42
  2. B46
  3. C48
  4. D40

Correct answer

B. 46

Step-by-step solution

aligned & A (3, , 3) & B(-3,-7, ) & BA =6 i +( +7) j +(3- ) k aligned p q = | array ccc i & j & k 3 & -1 & 1 -3 & 2 & 4 array | | BA ( p q )| | p q | =3 30 36+15( +7)-3(3- )=(3 30 )^2 aligned & 36+15 +105-9+3 =270 & 15 +3 =138 & 5 + =46 aligned

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