JEE Main202523 Jan 2025Evening ShiftMathematicsThree Dimensional GeometryActual

The distance of the line x-2 2 = y-6 3 = z-3 4 from the point (1,4,0) along the line x 1 = y-2 2 = z+3 3 is :

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Correct answer

C. 14

Step-by-step solution

Line passing through (1,4,0) and parallel to x 1 = y-2 2 = z+3 3 is L: x-1 1 = y-4 2 = z 3 Any point on L:( +1,2 +4,3 ) Any point on x-2 2 = y-6 3 = z-3 4 is (2 +2,3 +6,4 +3) . array l +1=2 +2 2 +4=3 +6 3 =4 +3 array =1 =0 Point: (2,6,3) aligned & Distance = (2-1)^2+(6-4)^2+(3-0)^2 & = 1+4+9 = 14 aligned

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