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JEE Main 202313 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
13 April
Shift
Evening Shift
Subject
Mathematics
Chapter
Three Dimensional Geometry

JEE Main 2023 · 13 April · Evening Shift · Mathematics · Three Dimensional Geometry

The plane, passing through the points ( 0, – 1, 2 ) and ( – 1, 2, 1...

The plane, passing through the points (0,–1,2)( 0, – 1, 2 ) and (–1,2,1)( – 1, 2, 1 ) and parallel to the line passing through (5,1,–7)( 5, 1, – 7 ) and (1,–1,–1),( 1, – 1, – 1 ) ,also passes through the point

Options

  1. A(−2,5,0)\left(- 2, 5, 0\right)
  2. B(1,−2,1)\left(1, - 2, 1\right)
  3. C(2,0,1)\left(2, 0, 1\right)
  4. D(0,5,−2)\left(0, 5, - 2\right)

Correct answer

A. (−2,5,0)\left(- 2, 5, 0\right)

Step-by-step solution

Let A(0,−1,2) and B(−1,2,1)A\left(0, - 1, 2\right) \text{ and } B\left(- 1, 2, 1\right) and given plane is parallel to line passing through \left(5, 1, - 7\right) \text{ and } \left(1, - 1, - 1\right)</p><p>So,normalvectortotheplaneisgivenby,</p><p></p><p>So, normal vector to the plane is given by,</p><p>\overset{\to}{n} = \left|\begin{cases}\overset{^}{i} & \overset{^}{j} & \overset{^}{k} \\ - 1 - 0 & 2 + 1 & 1 - 2 \\ 1 - 5 & - 1 - 1 & - 1 + 7\end{cases}\right|</p><p></p><p>⇒ \overset{\to}{n} = \left|\begin{cases}\overset{^}{i} & \overset{^}{j} & \overset{^}{k} \\ - 1 & 3 & - 1 \\ - 4 & - 2 & 6\end{cases}\right| = \overset{^}{i}\left(16\right) - \overset{^}{j}\left(- 10\right) + \overset{^}{k}\left(14\right)</p><p></p><p>⇒ \overset{\to}{n} = 16\overset{^}{i} + 10\overset{^}{j} + 14\overset{^}{k}</p><p></p><p>∴Equationofplane</p><p>Equation of plane</p><p>16 ( x – 0 ) + 10 ( y + 1 ) + 14 ( z – 2 ) = 0</p><p></p><p>⇒ 8x + 5y + 7z = 9</p><p>Nowsatisfyingthepointsfromoptionintheplaneweget,</p><p>(−2,5,0)</p><p>Now satisfying the points from option in the plane we get, </p><p>\left(- 2, 5, 0\right) only point which satisfy the plane.

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