- Exam
- JEE Main
- Year
- 2023
- Date
- 13 April
- Shift
- Evening Shift
- Subject
- Mathematics
- Chapter
- Three Dimensional Geometry
JEE Main 2023 · 13 April · Evening Shift · Mathematics · Three Dimensional Geometry
The plane, passing through the points ( 0, – 1, 2 ) and ( – 1, 2, 1...
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
Let and given plane is parallel to line passing through \left(5, 1, - 7\right) \text{ and } \left(1, - 1, - 1\right)\overset{\to}{n} = \left|\begin{cases}\overset{^}{i} & \overset{^}{j} & \overset{^}{k} \\ - 1 - 0 & 2 + 1 & 1 - 2 \\ 1 - 5 & - 1 - 1 & - 1 + 7\end{cases}\right|⇒ \overset{\to}{n} = \left|\begin{cases}\overset{^}{i} & \overset{^}{j} & \overset{^}{k} \\ - 1 & 3 & - 1 \\ - 4 & - 2 & 6\end{cases}\right| = \overset{^}{i}\left(16\right) - \overset{^}{j}\left(- 10\right) + \overset{^}{k}\left(14\right)⇒ \overset{\to}{n} = 16\overset{^}{i} + 10\overset{^}{j} + 14\overset{^}{k}∴16 ( x – 0 ) + 10 ( y + 1 ) + 14 ( z – 2 ) = 0⇒ 8x + 5y + 7z = 9 only point which satisfy the plane.