JEE Main202313 Apr 2023Evening ShiftMathematicsThree Dimensional GeometryActual
Let N be the foot of perpendicular from the point P ( 1 , - 2 , 3 ) on the line passing through the points ( 4 , 5 , 8 ) and ( 1 , - 7 , 5 ) . Then the distance of N from the plane 2 x - 2 y + z + 5 = 0 is
Options
- A8
- B6
- C9
- D7
Correct answer
D. 7
Step-by-step solution
Given, N be the foot of perpendicular from the point   P ( 1 , - 2 , 3 ) on the line passing through the points ( 4 , 5 , 8 ) and ( 1 , - 7 , 5 ) , Now finding direction ratio of line L we get, 4 - 1 , 5 + 7 , 8 - 5 ≡ 3 , 12 , 3 ≡ 1 , 4 , 1 Hence, the equation of Line will be, L : x - 1 1 = y + 7 4 = z - 5 1 = r Now let point N ≡ ( r + 1 , 4 r - 7 , r + 5 ) And given P ≡ ( 1 , - 2 , 3 ) So, direction ratio of P N ( r ,   4 r - 5 ,   r + 2 ) Since, P N ⊥ L so by perpendic