JEE Main202331 Jan 2023Evening ShiftMathematicsThree Dimensional GeometryActual
Let the plane P : 8 x + α 1 y + α 2 z + 12 = 0 be parallel to the line L : x + 2 2 = y - 3 3 = z + 4 5 . If the intercept of P on the y -axis is 1 , then the distance between P and L is
Options
- A2 7
- B6 14
- C7 2
- D14
Correct answer
D. 14
Step-by-step solution
Given, The plane P : 8 x + α 1 y + α 2 z + 12 = 0 be parallel to the line L : x + 2 2 = y - 3 3 = z + 4 5 and the intercept of P on the y -axis is 1 , Now normal of the plane will be perpendicular to the given line, so by perpendicular condition we get, ⇒ 8 × 2 + 3 α 1 + 5 α 2 = 0                     … 1 For Y intercept of plane put x = z = 0 in equation of plane ⇒ y = - 12 α 1 = 1 ⇒ α 1 = - 12 Put α 1