JEE Main202330 Jan 2023Morning ShiftMathematicsThree Dimensional GeometryActual
The line l 1 passes through the point 2 , 6 , 2 and is perpendicular to the plane 2 x + y - 2 z = 10 . Then the shortest distance between the line l 1 and the line x + 1 2 = y + 4 - 3 = z 2 is:
Options
- A7
- B19 3
- C19 2
- D9
Correct answer
D. 9
Step-by-step solution
The line l 1 passes through the point ( 2 ,   6 ,   2 ) and is perpendicular to the line 2 x + y - 2 z = 10 then, l 1 :   x - 2 2 = y - 6 1 = z - 2 - 2 Let the shortest distance between l 1 and the line x + 1 2 = y + 4 - 3 = z 2 is S.D. S.D. = A B → · M N → M N → Here, A B → = 3 i ^ + 10 j ^ + 2 k ^ M N → = i ^ j ^ k ^ 2 1 - 2 2 - 3 2 = - 4 i ^ - 8 j ^ - 8 k ^ ⇒ M N → = 16 + 64 + 64 = 12 A B → · M N → = - 12 - 80 - 16 = - 108 So, shortes