JEE Main202330 Jan 2023Morning ShiftMathematicsThree Dimensional GeometryActual
If the equation of the plane passing through the point ( 1 , 1 , 2 ) and perpendicular to the line x - 3 y + 2 z - 1 = 0 = 4 x - y + z is A x + B y + C z = 1 , then 140 ( C - B + A ) is equal to
Correct answer
0
Step-by-step solution
Equation of the required plane is a x - 1 + b y - 1 + c z - 2 = 0       . . . . i Since, required plane is perpendicular to the line x - 3 y + 2 z - 1 = 0 = 4 x - y + z , therefore normal vector of the plane is n → = i ^ j ^ k ^ 1 - 3 2 4 - 1 1 ⇒ n → = - i ^ + 7 j ^ + 11 k ^ So, direction ratios of normal to the plane is - 1 , 7 , 11 Equation of plane is - 1 ( x - 1 ) + 7 ( y - 1 ) + 11 ( z - 2 ) = 0 ⇒ - x + 7 y + 11 z = 28 ⇒ x - 28 + 7 y 28 + z 28 11 = 1 Comparing with