JEE Main 202622 JanuaryEvening Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 22 January
- Shift
- Evening Shift
- Subject
- Physics
- Chapter
- Capacitance
JEE Main 2026 · 22 January · Evening Shift · Physics · Capacitance
A capacitor P with capacitance 10 × 10^ -6 ~F is fully charged with...
A capacitor with capacitance is fully charged with a potential difference of 6.0 V and disconnected from the battery. The charged capacitor is connected across another capacitor with capacitance . The charge on capacitor when equilibrium is established will be (assume capacitor does not have any charge initially), the value of is 。
Correct answer
0
Step-by-step solution
Capacitor P (10 × 10⁻⁶ F) is charged to 6.0 V.
Initial charge: C.
When connected to uncharged capacitor Q (20 × 10⁻⁶ F), charge redistributes until both reach same potential.
Final voltage: V.
Charge on Q: C = C.
Thus .
Initial charge: C.
When connected to uncharged capacitor Q (20 × 10⁻⁶ F), charge redistributes until both reach same potential.
Final voltage: V.
Charge on Q: C = C.
Thus .