JEE Main20253 Apr 2025Evening ShiftPhysicsCapacitanceActual
Using a battery, a 100 pF capacitor is charged to 60 V and then the battery is removed. After that, a second uncharged capacitor is connected to the first capacitor in parallel. If the final voltage across the second capacitor is 20 V, its capacitance is : (in pF)
Options
- A600
- B200
- C400
- D100
Correct answer
B. 200
Step-by-step solution
New potential = C ₀ ~V ₀ C ₀+ C = V ₀ 3 aligned & 3 C ₀ ~V ₀= C ₀ ~V ₀+ CV ₀ & 2 C ₀ ~V ₀= CV ₀ & C 2 C ₀ aligned