JEE Main202524 Jan 2025Morning ShiftPhysicsCapacitanceActual
Consider a parallel plate capacitor of area A (of each plate) and separation 'd' between the plates. If E is the electric field and ₀ is the permittivity of free space between the plates, then potential energy stored in the capacitor is
Options
- A₀ E ^2 Ad
- B1 2 ₀ E ^2 Ad
- C1 4 ₀ E ^2 Ad
- D3 4 ₀ E ^2 Ad
Correct answer
B. 1 2 ₀ E ^2 Ad
Step-by-step solution
We know energy density _ av = 1 2 ₀ E^2 So potential energy = _ a v Volume P.E. = 1 2 ₀ E^2 A d