Three capacitors of capacitances 25 μ F, 30 μ F and 45 μ F are connected in parallel to a supply of 100 ~V . Energy stored in the above combination is E. When these capacitors are connected in series to the same supply

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In parallel combination : Potential difference is same across all aligned & Energy =(1)/(2)(C_1+C_2+C_3) V^2 & =(1)/(2)(25+30+45) ×(100)^2 × 10^ -6 =0.5=E aligned In series combination: Charge is same on all. aligned & 1 C_ equ = 1 C_1 + 1 C_2 + 1 C_3 =(1)/(25)+(1)/(30)+(1)/(45) & 1 C_ equ =((18+15+10))/(450)=(43)/(450) C_ equ =(450)/(43) & Energy = Q^2 2 C_1 + Q^2 2 C_2 + Q^2 2 C_3 & = Q^2 2 [ 1 C_1 + 1 C_2 + 1 C_3 ] & (V × C_ equ )^2 2 × 1 C_ equ = V^2 C_ equ 2 & ((100)^2)/(2) × (450)/(43) × 10^ -6 & (4.5)/(86)= 9 x E= 9 x × 0.5 x=86 aligned

Three capacitors of capacitances 25 μ F, 30 μ F and 45 μ F are...

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