JEE Main202311 Apr 2023Evening ShiftPhysicsCapacitanceActual
A capacitor of capacitance C is charged to a potential V . The flux of the electric field through a closed surface enclosing the positive plate of the capacitor is:
Options
- ACV ε 0
- BZero
- C2 CV ε 0
- DCV 2 ε 0
Correct answer
A. CV ε 0
Step-by-step solution
The charge enclosed is given by q i n c = C V Gauss' law states that the flux through any closed surface is equal to the charge enclosed by the surface. Using Gauss' law the flux is, ϕ = q inc  ε 0 = C V ε 0