Two capacitors, each having capacitance 40 μ F are connected in series. The space between one of the capacitors is filled with dielectric material of dielectric constant K such that the equivalence capacitance of the system became 24 &

Question

Two capacitors, each having capacitance 40 &#956; F are connected in series. The space between one of the capacitors is filled with dielectric material of dielectric constant K such that the equivalence capacitance of the system became 24 &#956; F . The value of K will be :

Quantrex Academy · Accepted Answer

Correct answer: A. 1 . 5

When a dielectric is inserted between the sheets of a capacitor, its capacitance becomes K C . Now the equivalent capacitance in series combination will be, C eq = C &#215; K C C 1 + K &#8658; 24 = 40 K 1 + K &#8658; K = 1 . 5

Two capacitors, each having capacitance 40 μ F are connected in series. The space between one of the capacitors is filled with dielectric material of dielectric constant K such that the equivalence capacitance of the system became 24 μ F . The value of K will be :

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Correct answer

Step-by-step solution

More from Capacitance

Two capacitors, each having capacitance 40 &#956; F are connected in series. The space between one of the capacitors is filled with dielectric material of dielectric constant K such that the equivalence capacitance of the system became 24 &#956; F . The value of K will be :

Options

Correct answer

Step-by-step solution

More from Capacitance

Two capacitors, each having capacitance 40 μ F are connected in series. The space between one of the capacitors is filled with dielectric material of dielectric constant K such that the equivalence capacitance of the system became 24 μ F . The value of K will be :