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JEE Main 202226 JulyMorning Shift
Exam
JEE Main
Year
2022
Date
26 July
Shift
Morning Shift
Subject
Physics
Chapter
Capacitance

JEE Main 2022 · 26 July · Morning Shift · Physics · Capacitance

The total charge on the system of capacitance C _ 1 = 1μ F, C _ 2 =...

The total charge on the system of capacitance C1=1μF,C2=2μF,C3=4μF{C}_{1} = 1\mu F, {C}_{2} = 2\mu F, {C}_{3} = 4\mu F and C4=3μF{C}_{4} = 3\mu F connected in parallel is
(Assume a battery of 20V20V is connected to the combination)

Options

  1. A200\muC200\muC
  2. B200C200C
  3. C10\muC10\muC
  4. D10C10C

Correct answer

A. 200\muC200\muC

Step-by-step solution

As the given capacitors are in parallel combination, therefore,Ceq=(1+2+3+4)μF=10μF{C}_{eq} = \left(1 + 2 + 3 + 4\right)\mu F = 10\mu F

Hence, charge flown through the switch∴Q=(20V)×(10μF)=200\muC∴ Q = \left(20V\right) \times \left(10\mu F\right) = 200\muC

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