A capacitor C _ 1 of capacitance 5 is charged to a potential of 30V...

A capacitor ${C}_{1}$ of capacitance $5\muF$ is charged to a potential of $30V$ using a battery. The battery is then removed and the charged capacitor is connected to an uncharged capacitor ${C}_{2}$ of capacitance $10\muF$ as shown in figure. When the switch is closed charge flows between the capacitors. At equilibrium, the charge on the capacitor ${C}_{2}$ is _____ $\muC$ .

A capacitor C _ 1 of capacitance 5 is charged to a potential of 30V using a battery. The battery is then removed and

Correct answer

Step-by-step solution

The initial charge on the $5\mu F$ capacitor will be $q = CV = 150\mu C$ . If the charge on the $10\mu F$ capacitor is $q$ after the key is closed then,

A capacitor C _ 1 of capacitance 5 is charged to a potential of 30V using a battery. The battery is then removed and

$\dfrac{150 - q}{5} = \dfrac{q}{10} ⇒ q = 100\mu C$

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