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JEE Main202226 Jun 2022Morning ShiftPhysicsCapacitanceActual

Two capacitors having capacitance C 1 and C 2 respectively are connected as shown in figure. Initially, capacitor C 1 is charged to a potential difference V volt by a battery. The battery is then removed and the charged capacitor C 1 is now connected to uncharged capacitor C 2 by closing the switch S . The amount of charge on the capacitor C 2 , after equilibrium, is

Options

  1. AC 1 C 2 C 1 + C 2 V
  2. BC 1 + C 2 C 1 C 2 V
  3. CC 1 + C 2 V
  4. DC 1 - C 2 V

Correct answer

A. C 1 C 2 C 1 + C 2 V

Step-by-step solution

The initial charge on the capacitor C 1 will be Q = C 1 V . If after closing the switch the charge flown through the circuit is q , the charge on C 2 will be q and C 1 will be Q - q . The potential across the capacitors will be same. Hence, Q - q C 1 = q C 2 ⇒ q = C 2 Q C 1 + C 2 ⇒ q = C 1 C 2 C 1 + C 2 V

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