A parallel plate capacitor of capacitance 200 is connected to a...

A parallel plate capacitor of capacitance

200\muF

is connected to a battery of

200V .

A dielectric slab of dielectric constant

2

is now inserted into the space between plates of capacitor while the battery remain connected. The change in the electrostatic energy in the capacitor will be __________

J .

Correct answer

Step-by-step solution

Initially

C = 200\muF

{E}_{i} = \dfrac{1}{2}C{V}^{2} = \dfrac{1}{2} \times \left(200 \times {10}^{- 6}\right) \times {\left(200\right)}^{2}

Finally

{C}^{'} = KC = 400\muF

{E}_{f} = \dfrac{1}{2}{C}^{'}{V}^{2} = \dfrac{1}{2} \times \left(400 \times {10}^{- 6}\right) \times ( 200{)}^{2}

\Delta E = \dfrac{1}{2} \times \left[\left(400 - 200\right) \times {10}^{- 6}\right] \times 4 \times {10}^{4} = 4J

Practice Capacitance on Quantrex Academy →

More from Capacitance

Passage: A container of height 2 m, length 2 m and breadth 1 m is made of insulating… JEE Advanced 2026 A parallel plate capacitor is having separation between plates 0.885 mm. It has a… JEE Main 2026 A sphere of capacitance 100 pF is charged to a potential of 100 V. Another identical… JEE Main 2026 From the circuit given below, the capacitance between terminals A and B shown in the… JEE Main 2026 A parallel plate air capacitor is connected to a battery. The plates are pulled apart at… JEE Main 2026 Consider a circuit consisting of a capacitor ( 20\ μ F), resistor ( 100\ Ω ) and two… JEE Main 2026 The dimensional formula of (1)/(2)ε_0 E^2 ( ε_0 = permittivity of vacuum and E = electric… JEE Main 2026 A parallel plate air capacitor has a capacitance C . When it is half filled as show in… JEE Main 2026 Full Capacitance list All JEE Main PYQs