Three capacitors C 1 = 2 μ F , C 2 = 6 μ F and C 3 = 12 μ F are connected as shown in the figure. Find the ratio of the charges on capacitors C 1 , C 2 and C 3 respectively.

Step-by-step solution

From the above circuit diagram, the equivalent capacitance of the combination of capacitors is, C eq = C 1 + C 2 C 3 C 2 C 3 , C eq = 2 + 6 × 12 6 + 12 = 6   μ F Then, Q C 1 Q C 2 = C 1 V C 2 C 3 C 2 + C 3 V = 2 × ( 6 + 12 ) 6 × 12 = 1 2 and Q C 2 = Q C 3 So, the ratio of charges are, 1 : 2 : 2 .