A parallel-plate capacitor with plate area A has separation d between the plates. Two dielectric slabs of dielectric constant K 1 and K 2 of same area A 2 and thickness d 2 are inserted in the space between the plates. The capacitance of th

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A parallel-plate capacitor with plate area A has separation d between the plates. Two dielectric slabs of dielectric constant K 1 and K 2 of same area A 2 and thickness d 2 are inserted in the space between the plates. The capacitance of the capacitor will be given by :

Quantrex Academy · Accepted Answer

Correct answer: A. &#949; 0 &#160; A &#160; d 1 2 + K 1 &#160; K 2 &#160; K 1 + K 2

C eq = C 1 + C 2 C 3 C 2 + C 3 C eq = A &#949; 0 2 &#160; d + K 1 &#160; A &#949; 0 &#160; d &#215; K 2 &#160; A &#949; 0 &#160; d K 1 &#160; A &#949; 0 &#160; d + K 2 &#160; A &#949; 0 &#160; d C eq = A &#949; 0 2 &#160; d + A &#949; 0 &#160; d K 1 &#160; K 2 &#160; K 1 + K 2 = A &#949; 0 &#160; d 1 2 + K 1 &#160; K 2 &#160; K 1 + K 2

A parallel-plate capacitor with plate area A has separation d between the plates. Two dielectric slabs of dielectric constant K 1 and K 2 of same area A 2 and thickness d 2 are inserted in the space between the plates. The capacitance of the capacitor will be given by :

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