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JEE Main20204 Sep 2020Evening ShiftPhysicsCapacitanceActual

A capacitor C is fully charged with voltage V 0 . After disconnecting the voltage source, it is connected in parallel with another uncharged capacitor of capacitance C 2 . The energy loss in the process after the charge is distributed between the two capacitors is :

Options

  1. A1 2 C V 0 2
  2. B1 3 C V 0 2
  3. C1 4 C V 0 2
  4. D1 6 C V 0 2

Correct answer

D. 1 6 C V 0 2

Step-by-step solution

Heat Loss is given by, H = C 1 C 2 2 C 1 + C 2 V 1 - V 2 2 V 1 is initial voltage of capacitor C = V 0 V 2 is the initial voltage of capacitor C 2 = 0 = c × c 2 2 c + c 2 V 0 - 0 2 = C 6 V 0 2 H = 1 6 C 0 V 0 2

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