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JEE Main20208 Jan 2020Morning ShiftPhysicsCapacitanceActual

Effective capacitance of parallel combination of two capacitors C 1 and C 2 is 10 μ F . When these capacitors are individually connected to a voltage source of 1 V , the energy stored in the capacitor C 2 is 4 times that of C 1 . If these capacitors are connected in series, their effective capacitance will be:

Options

  1. A4.2 μ F
  2. B3.2 μ F
  3. C1.6 μ F
  4. D8.4 μ F

Correct answer

C. 1.6 μ F

Step-by-step solution

Given C 1 + C 2 = 10 μ F ...(i) 4 1 2 C 1 V 2 = 1 2 C 2 V 2 ⇒ 4 C 1 = C 2 ...(ii) From equation (i) and (ii) C 1 = 2 μ F C 2 = 8 μ F If they are in series C e q = C 1 C 2 C 1 + 2 = 1.6 μ F

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