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JEE Main 201911 JanuaryEvening Shift
Exam
JEE Main
Year
2019
Date
11 January
Shift
Evening Shift
Subject
Physics
Chapter
Capacitance

JEE Main 2019 · 11 January · Evening Shift · Physics · Capacitance

Seven capacitors, each of capacitance 2 μ F, are to be connected in...

Seven capacitors, each of capacitance 2μF,2 \mu \mathrm{F}, are to be connected in a configuration to obtain an effective capacitance of \left(\frac{6}{13}\right) \mu \mathrm{F} . Which of the combinations, shown in figures below, will achieve the desired value?Seven capacitors, each of capacitance 2 μ F, are to be connected in a configuration to obtain an effective capacitanceSeven capacitors, each of capacitance 2 μ F, are to be connected in a configuration to obtain an effective capacitanceSeven capacitors, each of capacitance 2 μ F, are to be connected in a configuration to obtain an effective capacitanceSeven capacitors, each of capacitance 2 μ F, are to be connected in a configuration to obtain an effective capacitanceSeven capacitors, each of capacitance 2 μ F, are to be connected in a configuration to obtain an effective capacitance

Options

  1. AThe basic character of the transition metal monoxides follows the order: (Atomic nos. Ti=22, ~V=23, Cr=24, Fe =26 )
  2. BThe basic character of the transition metal monoxides follows the order: (Atomic nos. Ti=22, ~V=23, Cr=24, Fe =26 )
  3. CThe basic character of the transition metal monoxides follows the order: (Atomic nos. Ti=22, ~V=23, Cr=24, Fe =26 )
  4. DThe basic character of the transition metal monoxides follows the order: (Atomic nos. Ti=22, ~V=23, Cr=24, Fe =26 )

Correct answer

B. The basic character of the transition metal monoxides follows the order: (Atomic nos. Ti=22, ~V=23, Cr=24, Fe =26 )

Step-by-step solution

As required equivalent capacitance should be Ceq=613μFC_{\mathrm{eq}}=\frac{6}{13} \mu \mathrm{F} Therefore three capacitors must be in parallel and 4 must be in series with it. 1Ceq=\frac{1}{\mathrm{C}_{\mathrm{eq}}}=\left[\frac{1}{3 \mathrm{C}}\right]+[1C+1C+1C+1C]\left[\frac{1}{\mathrm{C}}+\frac{1}{\mathrm{C}}+\frac{1}{\mathrm{C}}+\frac{1}{\mathrm{C}}\right] Ceq=3C13=613μF[C_{\mathrm{eq}}=\frac{3 \mathrm{C}}{13}=\frac{6}{13} \mu \mathrm{F} \quad[ as C=2μF]\mathrm{C}=2 \mu \mathrm{F}] So, desired combination will be as below: Seven capacitors, each of capacitance 2 μ F, are to be connected in a configuration to obtain an effective capacitance
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