In the following circuit the switch S is closed at t = 0 . The charge on the capacitor C 1 as a function of time will be given by C e q = C 1 C 2 C 1 + C 2

Step-by-step solution

In given circuit capacitors C 1 and C 2 are connected in series , so equivalent capacitance will be 1 C e q = 1 C 1   + 1 C 2   ⇒ C e q = C 1 C 2 C 1 + C 2   at t   =   0 , the switch is closed and capacitors start charged, at time t charge on the capacitor is given by q =   q 0   1 - e - t / τ where q 0 is the maximum charge on the capacitor at steady state and τ is the time constant. and q 0   = C e q E and τ   =   R C e q Then from the above