A capacitance of 2μ F is required in an electrical circuit across a...

Let us assume that we connect $n$(whole number) capacitors in series such that the potential difference across the combination is $1000V$. This means the potential difference across each capacitor is

${V}_{capacitor} = \dfrac{1000}{n}V \le 300V$

$n ⩾ \dfrac{1000}{300} = 3 . 333$.

{n}_\min = 4

This means we need to connect at least $4$ capacitors in series to make sure that the potential across each one is less than $300V$.

${C}_{eq} = \dfrac{m}{n}C = 2\mu F$

$\dfrac{m}{4} = 2 ⇒ m = 8$

$∴$ Minimum no. of capacitors $= 8 \times 4 = 32$