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JEE Main 20149 AprilOnline
Exam
JEE Main
Year
2014
Date
9 April
Mode
Online
Subject
Physics
Chapter
Capacitance

JEE Main 2014 · 9 April · Online · Physics · Capacitance

Three capacitances, each of 3 μ F , are provided. These cannot be...

Three capacitances, each of 3 μF\mu \text{F}, are provided. These cannot be combined to provide the resultant capacitance of :

Three capacitances, each of 3 μ F , are provided. These cannot be combined to provide the resultant capacitance of :Three capacitances, each of 3 μ F , are provided. These cannot be combined to provide the resultant capacitance of :Three capacitances, each of 3 μ F , are provided. These cannot be combined to provide the resultant capacitance of :Three capacitances, each of 3 μ F , are provided. These cannot be combined to provide the resultant capacitance of :

Options

  1. A2 μ \text{F}
  2. B6μF6 \mu \text{F}
  3. C1.5μF1.5 \mu \text{F}
  4. D1 μ \text{F}

Correct answer

B. 6μF6 \mu \text{F}

Step-by-step solution

Equivalent capacitance will be maximum for parallel combination and Minimum for series combination

∴∴ Possibilities are

1) Three capacitances, each of 3 μ F , are provided. These cannot be combined to provide the resultant capacitance of : C=1μF\text{C} = 1 \mu \text{F}

2) Three capacitances, each of 3 μ F , are provided. These cannot be combined to provide the resultant capacitance of : C=9μF\text{C} = 9 \mu \text{F}

3) Three capacitances, each of 3 μ F , are provided. These cannot be combined to provide the resultant capacitance of : 1C=16+13=36\dfrac{1}{\text{C}} = \dfrac{1}{6} + \dfrac{1}{3} = \dfrac{3}{6}

∴C=2μF∴ \text{C} = 2 \mu \text{F}

4) Three capacitances, each of 3 μ F , are provided. These cannot be combined to provide the resultant capacitance of : C=C2+C=32×C\text{C} = \dfrac{\text{C}}{2} + \text{C} = \dfrac{3}{2} \times \text{C}

=32=1.5μF= \dfrac{3}{2} = \text{1.5} \mu \text{F}
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