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JEE Main 201226 MayOnline
Exam
JEE Main
Year
2012
Date
26 May
Mode
Online
Subject
Physics
Chapter
Capacitance

JEE Main 2012 · 26 May · Online · Physics · Capacitance

This question has Statement 1 and Statement 2 . Of the four choices...

This question has Statement 1 and Statement 2 . Of the four choices given after the Statements, choose the one that best describes the two Statements. Statement 1: It is not possible to make a sphere of capacity 1 farad using a conducting material. Statement 2: It is possible for earth as its radius is 6.4×106 m6.4 \times 10^6 \mathrm{~m}.

Options

  1. AStatement 1 is true, Statement 2 is true, Statement 2 is the correct explanation of Statement 1.
  2. BStatement 1 is false, Statement 2 is true.
  3. CStatement 1 is true, Statement 2 is true, Statement 2 is not the correct explanation of Statement 1.
  4. DStatement 1 is true, Statement 2 is false.

Correct answer

D. Statement 1 is true, Statement 2 is false.

Step-by-step solution

Capacitance of sphere is given by: C=4πϵ0rC=4 \pi \epsilon_0 r If, C=1 FC=1 \mathrm{~F} then radius of sphere needed: r=C4πϵ0=14π×8.85×10−12r=\frac{C}{4 \pi \epsilon_0}=\frac{1}{4 \pi \times 8.85 \times 10^{-12}} or, r=10124π×8.85=9×109 mr=\frac{10^{12}}{4 \pi \times 8.85}=9 \times 10^9 \mathrm{~m} 9×109 m9 \times 10^9 \mathrm{~m} is very large, it is not possible to obtain such a large sphere. Infact earth has radius 6.4×106 m6.4 \times 10^6 \mathrm{~m} only and capacitance of earth is 711μF711 \mu \mathrm{F}.
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