A series combination of n₁ capacitors, each of capacity C₁ is charged by source of potential difference 4 ~V . When another parallel combination of n₂ capacitors each of capacity C₂ is charged by a source of potential difference V , it has the same total energy stored in it as the first combination has. The value of C₂ in terms of C₁ is then

Step-by-step solution

Equivalent capacitance of n₂ number of capacitors each of capacitance C ₂ in parallel =n₂ C₂ Equivalent capacitance of n₁ number of capacitors each of capacitances C ₁ in series. Capacitance of each is C₁= C₁ n₁ According to question, total energy stored in both the combinations are same aligned & i.e., 1 2 ( C₁ n₁ )(4 V)^2= 1 2 (n₂ C₂ b ^2 . & C₂= 16 C₁ n₁ n₂ & aligned