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JEE Main 2003
Exam
JEE Main
Year
2003
Subject
Physics
Chapter
Capacitance

JEE Main 2003 · Physics · Capacitance

The work done in placing a charge of 8 × 10^ -18 coulomb on a...

The work done in placing a charge of 8×10−188 \times 10^{-18} coulomb on a condenser of capacity 100 micro-farad is

Options

  1. A16×10−3216 \times 10^{-32} joule
  2. B3.1×10−263.1 \times 10^{-26} joule
  3. C4×10−104 \times 10^{-10} joule
  4. D32×10−3232 \times 10^{-32} joule

Correct answer

D. 32×10−3232 \times 10^{-32} joule

Step-by-step solution

Work done =12q2c=(8×10−18)22×100×10−8=32×10−32 J=\frac{1}{2} \frac{\mathrm{q}^2}{\mathrm{c}}=\frac{\left(8 \times 10^{-18}\right)^2}{2 \times 100 \times 10^{-8}}=32 \times 10^{-32} \mathrm{~J}
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