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The work done in placing a charge of 8 10⁻¹⁸ coulomb on a condenser of capacity 100 micro-farad is

Options

  1. A16 10⁻³² joule
  2. B3.1 10⁻²⁶ joule
  3. C4 10⁻¹⁰ joule
  4. D32 10⁻³² joule

Correct answer

D. 32 10⁻³² joule

Step-by-step solution

Work done = 1 2 q ^2 c = (8 10⁻¹⁸ )^2 2 100 10⁻⁸ =32 10⁻³² ~J

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