JEE Main 20211 SeptemberEvening Shift
- Exam
- JEE Main
- Year
- 2021
- Date
- 1 September
- Shift
- Evening Shift
- Subject
- Physics
- Chapter
- Communication System
JEE Main 2021 · 1 September · Evening Shift · Physics · Communication System
A carrier wave with amplitude of 250V is amplitude modulated by a...
A carrier wave with amplitude of is amplitude modulated by a sinusoidal base band signal of amplitude The ratio of minimum amplitude to maximum amplitude for the amplitude modulated wave is then value of is _________ .
Correct answer
200
Step-by-step solution
The value of maximum amplitude, {A}_\max = {A}_{c} + {A}_{m} = \left(250 + 150\right)V = 400V
, and the value of minimum amplitude,{A}_\min = {A}_{c} - {A}_{m} = \left(250 - 150\right)V = 100V
⇒ \dfrac{{A}_\min}{{A}_\max} = \dfrac{100V}{400V} = \dfrac{1}{4} = \dfrac{50}{200}
, and the value of minimum amplitude,{A}_\min = {A}_{c} - {A}_{m} = \left(250 - 150\right)V = 100V
⇒ \dfrac{{A}_\min}{{A}_\max} = \dfrac{100V}{400V} = \dfrac{1}{4} = \dfrac{50}{200}