JEE Main20211 Sep 2021Evening ShiftPhysicsCommunication SystemActual
A carrier wave with amplitude of 250     V is amplitude modulated by a sinusoidal base band signal of amplitude 150     V . The ratio of minimum amplitude to maximum amplitude for the amplitude modulated wave is 50 :   x , then value of x , is _ _ _ _ _ _ _ _ _ .
Correct answer
200
Step-by-step solution
The value of maximum amplitude, A max = A c + A m = 250 + 150   V = 400   V , and the value of minimum amplitude, A min = A c - A m = 250 - 150   V = 100   V ⇒ A min A max = 100   V 400   V = 1 4 = 50 200 ⇒ x = 200   V