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JEE Main 201911 JanuaryEvening Shift
Exam
JEE Main
Year
2019
Date
11 January
Shift
Evening Shift
Subject
Physics
Chapter
Communication System

JEE Main 2019 · 11 January · Evening Shift · Physics · Communication System

An amplitude modulated signal is plotted below: Which one of the...

An amplitude modulated signal is plotted below: An amplitude modulated signal is plotted below: Which one of the following best describes the above signal?
Which one of the following best describes the above signal?

Options

  1. A(9+sin⁡(2.5π×105t))sin⁡(2π×104t)V\left(9+\sin \left(2.5 \pi \times 10^{5} \mathrm{t}\right)\right) \sin \left(2 \pi \times 10^{4} \mathrm{t}\right) \mathrm{V}
  2. B(1+9sin⁡(2π×104t))sin⁡(2.5π×105t)V\left(1+9 \sin \left(2 \pi \times 10^{4} \mathrm{t}\right)\right) \sin \left(2.5 \pi \times 10^{5} \mathrm{t}\right) \mathrm{V}
  3. C(9+sin⁡(2π×104t))sin⁡(2.5π×105t)V\left(9+\sin \left(2 \pi \times 10^{4} t\right)\right) \sin \left(2.5 \pi \times 10^{5} \mathrm{t}\right) \mathrm{V}
  4. D(9+sin⁡(4π×104t))sin⁡(5π×105t)V\left(9+\sin \left(4 \pi \times 10^{4} t\right)\right) \sin \left(5 \pi \times 10^{5} \mathrm{t}\right) \mathrm{V}

Correct answer

C. (9+sin⁡(2π×104t))sin⁡(2.5π×105t)V\left(9+\sin \left(2 \pi \times 10^{4} t\right)\right) \sin \left(2.5 \pi \times 10^{5} \mathrm{t}\right) \mathrm{V}

Step-by-step solution

After analysing the graph we may conclude that (i) Amplitude varies as 8−10 V8-10 \mathrm{~V} or 9±19 \pm 1 (ii) Two time period as 100μ100 \mu s (signal wave) &8μ\& 8 \mu (carrier wave) So, equation of AM signal is [9±1sin⁡(2πtT1)sin⁡(2πtT2)]=[9±sin⁡(2π×104t)]sin⁡(2.5π×105t)V\left[9 \pm 1 \sin \left(\frac{2 \pi t}{T_{1}}\right) \sin \left(\frac{2 \pi t}{T_{2}}\right)\right] =\left[9 \pm \sin \left(2 \pi \times 10^{4} \mathrm{t}\right)\right] \sin \left(2.5 \pi \times 10^{5} \mathrm{t}\right) \mathrm{V}
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