A cylindrical conductor of length 2 m and area of cross-section 0.2 ~mm^ 2 carries an electric current of 1.6 A when its ends are connected to a 2 V battery. Mobility of electrons in the conductor is α × 10^ -3 ~m^ 2 /

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For a cylindrical conductor with length 2 m, cross-section 0.2 mm² = 0.2 × 10⁻⁶ m², carrying 1.6 A at 2 V.
Resistance:

R = V/I = 2/1.6 = 1.25

Ω.
Resistivity:

\rho = RA/L = 1.25 \times 0.2 \times 10^{-6}/2

= 0.125 \times 10^{-6}

Ω·m.
Using

\rho = 1/(ne\mu)

, mobility:

\mu = 1/(ne\rho)

= 1/(5 \times 10^{28} \times 1.6 \times 10^{-19} \times 0.125 \times 10^{-6})

= 1/(1 \times 10^3) = 10^{-3}

m²/V·s.
Thus

\alpha = 1

.

A cylindrical conductor of length 2 m and area of cross-section 0.2...

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