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JEE Main 202622 JanuaryEvening Shift
Exam
JEE Main
Year
2026
Date
22 January
Shift
Evening Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2026 · 22 January · Evening Shift · Physics · Current Electricity

An electric power line having total resistance of 2 , delivers 1 kW...

An electric power line having total resistance of 2Ω2 \Omega, delivers 1 kW of power at 250 V. The percentage efficiency of transmission line is ____\_\_\_\_ .

Options

  1. A100
  2. B92.5
  3. C96.9
  4. D86.5

Correct answer

C. 96.9

Step-by-step solution

Current in transmission line: I=PV=1000250=4I = \frac{P}{V} = \frac{1000}{250} = 4 A.
Power loss: Ploss=I2R=42×2=32P_{loss} = I^2 R = 4^2 \times 2 = 32 W.
Efficiency: η=P−PlossP×100%\eta = \frac{P - P_{loss}}{P} \times 100\%
=1000−321000×100%= \frac{1000 - 32}{1000} \times 100\%
=96.8%= 96.8\% which rounds to 96.9%.
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