Exam

JEE Main

Year

2025

Date

7 April

Shift

Morning Shift

Subject

Physics

Chapter

Current Electricity

JEE Main 2025 · 7 April · Morning Shift · Physics · Current Electricity

A wire of resistance R is bent into a triangular pyramid as shown...

A wire of resistance $R$ is bent into a triangular pyramid as shown in figure with each segment having same length. The resistance between points $A$ and $B$ is $R / n$. The value of $n$ is :

Step-by-step solution

As $r=\frac{R}{6}$

(As balanced wheat stone bridge is formed) Now, Equivalent resistance between A and B can be written as
$\frac{1}{\mathrm{R}_{\mathrm{AB}}}=\frac{1}{2 \mathrm{r}}+\frac{1}{2 \mathrm{r}}+\frac{1}{\mathrm{r}}=\frac{2}{\mathrm{r}}$
$\mathrm{R}_{\mathrm{AB}}=\frac{\mathrm{R}}{12}$