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JEE Main 20254 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
4 April
Shift
Evening Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2025 · 4 April · Evening Shift · Physics · Current Electricity

From the combination of resistors with resistance values...

From the combination of resistors with resistance values R1=R2=R3=5ΩR_1=R_2=R_3=5 \Omega and R4=10ΩR_4=10 \Omega, which of the following combination is the best circuit to get an equivalent resistance of 6Ω6 \Omega ?From the combination of resistors with resistance values R_1=R_2=R_3=5 and R_4=10 , which of the following combinationFrom the combination of resistors with resistance values R_1=R_2=R_3=5 and R_4=10 , which of the following combinationFrom the combination of resistors with resistance values R_1=R_2=R_3=5 and R_4=10 , which of the following combinationFrom the combination of resistors with resistance values R_1=R_2=R_3=5 and R_4=10 , which of the following combinationFrom the combination of resistors with resistance values R_1=R_2=R_3=5 and R_4=10 , which of the following combination

Options

  1. ALet ^ u = u _ 1 ^ i + u _ 2 ^ j + u _ 3 ^ k be a unit vector in ℝ ^ 3 and ^ w = 1 6 ( ^ i + ^ j + 2 ^ k ) . Given that
  2. BLet ^ u = u _ 1 ^ i + u _ 2 ^ j + u _ 3 ^ k be a unit vector in ℝ ^ 3 and ^ w = 1 6 ( ^ i + ^ j + 2 ^ k ) . Given that
  3. CLet ^ u = u _ 1 ^ i + u _ 2 ^ j + u _ 3 ^ k be a unit vector in ℝ ^ 3 and ^ w = 1 6 ( ^ i + ^ j + 2 ^ k ) . Given that
  4. DLet ^ u = u _ 1 ^ i + u _ 2 ^ j + u _ 3 ^ k be a unit vector in ℝ ^ 3 and ^ w = 1 6 ( ^ i + ^ j + 2 ^ k ) . Given that

Correct answer

A. Let ^ u = u _ 1 ^ i + u _ 2 ^ j + u _ 3 ^ k be a unit vector in ℝ ^ 3 and ^ w = 1 6 ( ^ i + ^ j + 2 ^ k ) . Given that

Step-by-step solution

1RP=110+115=3+230=16\frac{1}{\mathrm{R}_{\mathrm{P}}}=\frac{1}{10}+\frac{1}{15}=\frac{3+2}{30}=\frac{1}{6}
From the combination of resistors with resistance values R_1=R_2=R_3=5 and R_4=10 , which of the following combination
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