Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 20245 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
5 April
Shift
Morning Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2024 · 5 April · Morning Shift · Physics · Current Electricity

In the experiment to determine the galvanometer resistance by...

In the experiment to determine the galvanometer resistance by half-deflection method, the plot of 1/θ1 / \theta vs the resistance (R)(\mathrm{R}) of the resistance box is shown in the figure. The figure of merit of the galvanometer is _____ ×10−1 A/\times 10^{-1} \mathrm{~A} / division. [The source has emf 2V] In the experiment to determine the galvanometer resistance by half-deflection method, the plot of 1 / θ vs the

Correct answer

0

Step-by-step solution

i=Kθ2G+R=Kθ⇒1θ=(G+R)K2=R(K2)+KG2 Slope =K2=14⇒K=0.5=5×10−1A\begin{aligned} & i=K \theta \\ & \frac{2}{G+R}=K \theta \\ & \Rightarrow \frac{1}{\theta}=\frac{(G+R) K}{2}=R\left(\frac{K}{2}\right)+\frac{K G}{2} \\ & \text{ Slope }=\frac{K}{2}=\frac{1}{4} \Rightarrow K=0.5=5 \times 10^{-1} A\end{aligned}
Practice Current Electricity on Quantrex Academy →

More from Current Electricity

A metal wire of cross-sectional area 0.5 mm ^2 and length 100 m is connected across a… JEE Advanced 2026As shown in the figure, the resistance of a galvanometer G can be found by the… JEE Advanced 2026The stored charge in the capacitor in steady state of the following circuit is ________ μ… JEE Main 2026A moving coil of galvanometer when shunted with 2\,Ω resistance gives a full scale… JEE Main 2026Two cells of emfs 1 V and 2 V and internal resistance 2\,Ω and 1\,Ω , respectively… JEE Main 2026Refer to the circuit diagram given below. The heat generated across the 6\,Ω resistance… JEE Main 2026In an experiment to determine the resistance of a given wire using Ohm's law, the… JEE Main 2026Under steady state condition the potential difference across the capacitor in the circuit… JEE Main 2026 Full Current Electricity list All JEE Main PYQs