JEE Main20244 Apr 2024Evening ShiftPhysicsCurrent ElectricityActual
An electric bulb rated 50 ~W -200 ~V is connected across a 100 ~V supply. The power dissipation of the bulb is:
Options
- A25 ~W
- B12.5 ~W
- C50 ~W
- D100 ~W
Correct answer
B. 12.5 ~W
Step-by-step solution
Rated power & voltage gives resistance aligned & R = V ^2 P = (200)^2 50 = 40000 50 & R =800 & P = ( V _ applied )^2 R = (100)^2 800 & P =12.5 watt aligned