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JEE Main 202429 JanuaryMorning Shift
Exam
JEE Main
Year
2024
Date
29 January
Shift
Morning Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2024 · 29 January · Morning Shift · Physics · Current Electricity

A galvanometer having coil resistance 10Ω shows a full scale...

A galvanometer having coil resistance 10Ω10Ω shows a full scale deflection for a current of 3mA3mA. For it to measure a current of 8A8A, the value of the shunt should be:A galvanometer having coil resistance 10Ω shows a full scale deflection for a current of 3mA . For it to measure a

Options

  1. A3×10−3Ω3 \times {10}^{- 3}Ω
  2. B4.85×10−3Ω4 . 85 \times {10}^{- 3}Ω
  3. C3.75×10−3Ω3 . 75 \times {10}^{- 3}Ω
  4. D2.75×10−3Ω2 . 75 \times {10}^{- 3}Ω

Correct answer

C. 3.75×10−3Ω3 . 75 \times {10}^{- 3}Ω

Step-by-step solution

Given G=10ΩG = 10Ω, Ig=3mA{I}_{g} = 3mA and I=8AI = 8A.

Let's consider the following figure:

A galvanometer having coil resistance 10Ω shows a full scale deflection for a current of 3mA . For it to measure a

From the figure, we have

IgG=(I−Ig)S⇒S=IgGI−Ig⇒S=(3×10−3)108−0.003=3.75×10−3Ω{I}_{g}G = \left(I - {I}_{g}\right)S ⇒ S = \dfrac{{I}_{g}G}{I - {I}_{g}} ⇒ S = \dfrac{\left(3 \times {10}^{- 3}\right)10}{8 - 0 . 003} = 3 . 75 \times {10}^{- 3}Ω

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