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JEE Main202429 Jan 2024Morning ShiftPhysicsCurrent ElectricityActual

The deflection in moving coil galvanometer falls from 25 divisions to 5 division when a shunt of 24 Ω is applied. The resistance of galvanometer coil will be:

Options

  1. A12 Ω
  2. B96 Ω
  3. C48 Ω
  4. D100 Ω

Correct answer

B. 96 Ω

Step-by-step solution

Let x represents the current per division though the galvanometer. After applying shunt Now, if G is the galvanometer resistance, from the above figure, it can be written that 5 x × G = 20 x × 24 ⇒ G = 4 × 24 ⇒ G = 96 Ω

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