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JEE Main 202427 JanuaryMorning Shift
Exam
JEE Main
Year
2024
Date
27 January
Shift
Morning Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2024 · 27 January · Morning Shift · Physics · Current Electricity

A wire of resistance R and length L is cut into 5 equal parts. If...

A wire of resistance RR and length LL is cut into 55 equal parts. If these parts are joined parallely, then resultant resistance will be :

Options

  1. AR25\dfrac{R}{25}
  2. BR5\dfrac{R}{5}
  3. C25R25R
  4. D5R5R

Correct answer

A. R25\dfrac{R}{25}

Step-by-step solution

Resistance of each part will be equally divided. So, the resistance of each part of the wire can be expressed as R5\dfrac{R}{5}.

The formula to calculate the equivalent resistance of the combination of resistors is given by

1Req=∑i=151Ri...(1)\dfrac{1}{{R}_{eq}} = \mathop{∑}_{i = 1}^{5}\dfrac{1}{{R}_{i}} . . . \left(1\right)

From equation (1), it follows that

1Req=5R+5R+5R+5R+5R=25R⇒Req=R25\dfrac{1}{{R}_{eq}} = \dfrac{5}{R} + \dfrac{5}{R} + \dfrac{5}{R} + \dfrac{5}{R} + \dfrac{5}{R} = \dfrac{25}{R} ⇒ {R}_{eq} = \dfrac{R}{25}

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