JEE Main202311 Apr 2023Evening ShiftPhysicsCurrent ElectricityActual
The current flowing through R 2 is :
Options
- A2 3   A
- B1 2   A
- C1 3   A
- D1 4   A
Correct answer
C. 1 3   A
Step-by-step solution
As can be seen from the first circuit above, C B   &   A B are in series which is in parallel with C A . So, the net resistance is R ' = 6 2   Ω = 3     Ω as shown in the second diagram. From the second diagram, D C   &   C A is in series which is parallel to D A . Hence the resistance is R ' ' = 6 × 3 ( 6 + 3 )   Ω = 2   Ω as shown in third diagram. From third diagram, both E D   &   D A are in series which is p