The current flowing through a conductor connected across a source is 2 A and 1 . 2 A at 0 o C and 100 o C respectively. The current flowing through the conductor at 50 o C will be _____ × 10 2 mA .

Step-by-step solution

By Ohm's law, V = I R . Let the current and resistance at 0 °   C be i 0   &   R 0 respectively. Let the current and resistance at 100   ° C   be i 100   &   R 100 respectively. By the given condition, i 0 R 0 = i 100 R 100 ⇒ 2 R 0 = 1 . 2 R 0 ( 1 + 100 α ) ⇒ 1 + 100 α = 5 3 ⇒ 50 α = 1 3 Since the voltage remains constant, i 50 R 50 = i 0 R 0 ⇒ i 50 = i 0 R 0 R 50 = 2 × R 0 R 0 1 + 50 α = 2 1 + 1 3 = 1 . 5 &#16