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JEE Main 202331 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
31 January
Shift
Evening Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2023 · 31 January · Evening Shift · Physics · Current Electricity

The H amount of thermal energy is developed by a resistor in 10s...

The HH amount of thermal energy is developed by a resistor in 10s10s when a current of 4A4A is passed through it. If the current is increased to 16A16A, the thermal energy developed by the resistor in 10s10s will be

Options

  1. AHH
  2. B16H16H
  3. CH4\dfrac{H}{4}
  4. D4H4H

Correct answer

B. 16H16H

Step-by-step solution

Heat energy developed in the resistor due to current is given by, H=i2RtH = {i}^{2}Rt. Therefore

⇒H∝i2⇒ H ∝ {i}^{2} (for t=t = constant)

Now required ratio, HH′=(416)2\dfrac{H}{{H}^{'}} = {\left(\dfrac{4}{16}\right)}^{2}

⇒H′=16H⇒ {H}^{'} = 16H

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