For the given circuit, in the steady state, | V _ B - V _ D | = _____ V .

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For the given circuit, in the steady state, | V _ B - V _ D | = _____ V .

At steady state current will not pass through capacitor, therefore effective resistance between B and C will be only $1Ω$ . Modified circuit will be as shown below.

For the given circuit, in the steady state, | V _ B - V _ D | = _____ V .

$⇒ {i}_{AB} = \dfrac{6}{3} = 2A$ and ${i}_{AD} = \dfrac{6}{12} = 0 . 5A$

Applying Kirchoff's law along path BAD, we get

$⇒ {V}_{B} + \left(2 \times 2\right) - \left(10 \times 0 . 5\right) = {V}_{D}$

$⇒ {V}_{B} - {V}_{D} = 1V$ .

For the given circuit, in the steady state, | V _ B - V _ D | =...

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